00:01
In this question, we're given this parametric equation.
00:04
X is 5t and y is 4t minus 1.
00:08
In part a, for t of values minus 3, minus 2, all the way to 3, we want to find the corresponding x and y value.
00:16
So just sub in for every t.
00:18
Just sub into the t for the x and for the y, and you'll find the pair of values here for every t.
00:29
In b, we want to find an algebra equation, that relates x and y.
00:36
So when x equals to 5 t, t is x over 5.
00:43
Now sub this into y equals to 4 t minus 1, sub into the t.
00:49
So we have 4 times x over 5 minus 1.
00:53
So y is 4 5x minus 1.
00:56
So y is 4 5x minus 1...