Can you solve the question with MATLAB, please?
The ethylene epoxidation is to be carried out using a cesium-doped silver catalyst in a packed-bed reactor.
C2H4+1/2O2→C2H4O -r1E = (k1E*PE*PO^0.58)/(1+K1E*PE)^2
Along with the desired reaction, the complete combustion of ethylene also occurs
C2H4+3O2→2CO2+2H2O -r2E = (k2E*PE*PO^0.3)/(1+K2E*PE)^2
It is proposed to replace the conventional PBR with a membrane reactor in order to improve the selectivity. As a rule of thumb, a 1% increase in the selectivity to ethylene oxide translates to an increase in profit of about $2 million/yr. The feed consists of 12% (mole) oxygen, 6% ethylene, and the remainder nitrogen at a temperature of 250°C and a pressure of 2 atm. The total molar flow rate is 0.0093 mol/s to a reactor containing 2 kg of catalyst.
k1E = 0.15 mol/(kg∙s∙atm^1.58) at 523 K with E1 = 60.7 kJ/mol
k2E = 0.0888 mol/(kg∙s∙atm^1.3) at 523 K with E2 = 73.2 kJ/mol
K1E = 6.50 atm^-1, K2E = 4.33 atm^-1
a) What conversion and selectivity of ethylene epoxide to CO2 are expected in a conventional PBR?
b) What would be the conversion and selectivity if the total molar flow rate were divided and the 12% oxygen stream (no ethylene) were uniformly fed through the sides of the membrane reactor, and 6% ethylene (no oxygen) were fed at the entrance?
c) Repeat (b) for a case when ethylene is fed uniformly through the sides and oxygen is fed at the entrance. Compare with parts (a) and (b). Describe what you find.