CD is a tangent to circle ABDEF at D. Chord AB is produced to C. Chord BE cuts chord AD in H and chord FD in G. AC || FD and FE = AB. a) Prove that D?? = D?? (3) b) Prove that ?BHD ||| ?FED (5) c) Hence AB/BH = FD/BD (3) [11]
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Since $CD$ is tangent to the circle at $D$, we have $\angle ADC = \angle BDA$ (tangent-chord property). Also, since $AC \parallel FD$, we have $\angle ADC = \angle FDB$. Show more…
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