00:01
First of all, we are going to try to find the lifetime of cesium 137, and then we'll be able to find the fraction of it remaining after a certain number of years.
00:15
So what we're after is the half -time t, and we know this is related to lambda in such a way.
00:35
T equals log l -n, which is a natural logarithm of 2, divided by lambda.
00:52
As they write it in the manual, 0 .693 divided by lambda.
01:04
So t being the half -life, it's given the problem to be 30 years.
01:17
So with this in mind, we can calculate lambda 0 .0231.
01:36
And the units of this would be years minus 1.
01:41
It's important to keep the units, of course.
01:49
So in a, what fraction remains after 120 years? well, we'll be using this formula here.
02:02
The number of atoms equal the number of original atoms, e to the minus lambda t...