Question

c) $f(x) = \sqrt{2x+1}$ d) 6. Find the Equation of the line through the points, (-2,2) and (1,8) 7. Find the equation of the line parallel to 2x-3y = 5 and (6, 1) lies on the graph 8. Find the equation of the line perpendicular to 2x + 5y = 3 that goes through (-1,1) 9. What is the line that goes through (-5, 2) with slope = 0

          c) $f(x) = \sqrt{2x+1}$ 
d) 
6. Find the Equation of the line through the points, (-2,2) and (1,8)
7. Find the equation of the line parallel to 2x-3y = 5 and (6, 1) lies on the graph
8. Find the equation of the line perpendicular to 2x + 5y = 3 that goes through (-1,1)
9. What is the line that goes through (-5, 2) with slope = 0

c) f(x) = √(2x+1)
d)
6. Find the Equation of the line through the points, (-2,2) and (1,8)
7. Find the equation of the line parallel to 2x-3y = 5 and (6, 1) lies on the graph
8. Find the equation of the line perpendicular to 2x + 5y = 3 that goes through (-1,1)
9. What is the line that goes through (-5, 2) with slope = 0

Added by Matthew G.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Yujie Wang

Step 1

To find the equation of a line parallel to 2x - 3y = 5, we need to find the slope of the given line. The equation is already in the form y = mx + b, where m is the slope. So, the slope of the given line is 2/3. Now, we have the slope and a point (6,1) that lies Show more…

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cfx = v2x + 1 6. Find the Equation of the line through the points (-2,2) and (1,8). 7. Find the equation of the line parallel to 2x - 3y = 5 and (6,1) lies on the graph. 8. Find the equation of the line perpendicular to 2x + 5y = 3 that goes through (-1,1). 9. What is the line that goes through (-5,2) with slope = 0.