Question

Challenge Titanium is a transition metal used in many alloys because it is extremely strong and lightweight. Titanium tetrachloride $(\mathrm{TiCl_{4 }})$ is extracted from titanium oxide $\left(\mathrm{TiO}_{2}\right)$ using chlorine and coke (carbon). $$\mathrm{TiO}_{2}(\mathrm{s})+\mathrm{C}(\mathrm{s})+2 \mathrm{Cl}_{2}(\mathrm{g}) \rightarrow \mathrm{TiCl}_{4}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{g})$$ \begin{equation} \mathrm{a. Cl}_{2} \text { gas is needed to react with } 1.25 \text { mol of } \mathrm{TIO}_{2} ? \end{equation} \begin{equation} \begin{array}{l}{\text { b. What mass of } C \text { is needed to react with } 1.25 \text { mol of TiO_{2} ? }} \\ {\text { c. What is the mass of all of the products formed by reaction with } 1.25 \text { mol of TiO_{2} ? }}\end{array} \end{equation}

          Challenge Titanium is a transition metal used in many alloys because it is extremely strong and lightweight. Titanium tetrachloride $(\mathrm{TiCl_{4 }})$ is
extracted from titanium oxide $\left(\mathrm{TiO}_{2}\right)$ using chlorine and coke (carbon).
$$\mathrm{TiO}_{2}(\mathrm{s})+\mathrm{C}(\mathrm{s})+2 \mathrm{Cl}_{2}(\mathrm{g}) \rightarrow \mathrm{TiCl}_{4}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{g})$$
\begin{equation}
\mathrm{a. Cl}_{2} \text { gas is needed to react with } 1.25 \text { mol of } \mathrm{TIO}_{2} ?
\end{equation}
\begin{equation}
\begin{array}{l}{\text { b. What mass of } C \text { is needed to react with } 1.25 \text { mol of TiO_{2} ? }} \\ {\text { c. What is the mass of all of the products formed by reaction with } 1.25 \text { mol of TiO_{2} ? }}\end{array}
\end{equation}

Added by Jennifer N.

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