00:01
So, in this problem, two vertical forces have been applied to a beam and suppose this is a beam that is already given in this question, this is 3 .22 at this intersection point, 4 .778, we have reason 1, 2 and 3 and now we will make a table of a elastic constant and then multiplication.
00:38
So, for the first reason is 8, second 6 and then 4.
00:44
So, this is for first reason, second reason and third reason, it is 7 .5, 4, 0 .5 and then multiplication is 16, 24 and 2 and the intuition to do this is to get the average value which is 86 and sum of it is 18.
01:11
So, the average value comes out to be 18, 6 divided by 18 and which is 4 .778 inches and now the neutral axis lies in the above of this face...