Question

Chapter Review 16. The height in metres of a projectile is modelled by the function \( h(t)=-5 t^{2}+25 \), where \( t \) is the time in seconds. a) Find the point when the object hits the ground. b) Find the average rate of change from the point when the projectile is launched \( (t=0) \) to the point in which it hits the ground. c) Estimate the object's speed at the point of impact.

          Chapter Review
16. The height in metres of a projectile is modelled by the function \( h(t)=-5 t^{2}+25 \), where \( t \) is the time in seconds.
a) Find the point when the object hits the ground.
b) Find the average rate of change from the point when the projectile is launched \( (t=0) \) to the point in which it hits the ground.
c) Estimate the object's speed at the point of impact.

Chapter Review
16. The height in metres of a projectile is modelled by the function h(t)=-5 t^2+25, where t is the time in seconds.
a) Find the point when the object hits the ground.
b) Find the average rate of change from the point when the projectile is launched (t=0) to the point in which it hits the ground.
c) Estimate the object's speed at the point of impact.

Added by -Ngeles J.

Calculus: Early Transcendentals

Jon Rogawski, Colin Adams, Robert… 4th Edition

Chapter 2

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Solved by Expert Brian Beasley

Step 1

- The object hits the ground when its height \( h(t) = 0 \). - Set the equation \( -5t^2 + 25 = 0 \). - Solve for \( t \): \[ -5t^2 + 25 = 0 \\ -5t^2 = -25 \\ t^2 = 5 \\ t = \sqrt{5} \approx 2.24 \] - The object hits the ground at approximately \( t = Show more…

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Chapter Review 16. The height in metres of a projectile is modelled by the function \( h(t)=-5 t^{2}+25 \), where \( t \) is the time in seconds. a) Find the point when the object hits the ground. b) Find the average rate of change from the point when the projectile is launched \( (t=0) \) to the point in which it hits the ground. c) Estimate the object's speed at the point of impact.