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CHE 112 - Bonus Assignment Acid/Base and Equilibrium (Due Aug 08, 12:20 PM) Name: To receive credit for this assignment, one of the learning assistants for this course should sign at right to indicate that you worked through this assignment with them. 1. (8 pts) Explain why silver oxalate ($Ag_2C_2O_4$, $K_{sp} = 5.40 \times 10^{-12}$) has a higher molar solubility than silver chloride ($AgCl$, $K_{sp} = 1.77 \times 10^{-10}$). Show the calculations that back up your explanation. 2. (5 pts) Identify each of the following 1:1 solution mixtures as acidic, basic, or neutral. Circle the correct choice. No justification is necessary. a) HF + KF ($pK_a = 4$) Acidic Neutral Basic b) $H_2SO_4$ + Na(HSO4) Acidic Neutral Basic c) KBr + NaBr Acidic Neutral Basic d) NaOH + NaBr Acidic Neutral Basic e) $NH_4Br$ + $NH_3$ ($pK_a = 9$) Acidic Neutral Basic

          CHE 112 - Bonus Assignment
Acid/Base and Equilibrium
(Due Aug 08, 12:20 PM)
Name:
To receive credit for this assignment, one of the learning assistants for this course should sign at right to
indicate that you worked through this assignment with them.
1. (8 pts) Explain why silver oxalate ($Ag_2C_2O_4$, $K_{sp} = 5.40 \times 10^{-12}$) has a higher molar solubility than silver
chloride ($AgCl$, $K_{sp} = 1.77 \times 10^{-10}$). Show the calculations that back up your explanation.
2. (5 pts) Identify each of the following 1:1 solution mixtures as acidic, basic, or neutral. Circle the
correct choice. No justification is necessary.
a) HF + KF ($pK_a = 4$)
Acidic	Neutral	Basic
b) $H_2SO_4$ + Na(HSO4)
Acidic	Neutral	Basic
c) KBr + NaBr
Acidic	Neutral	Basic
d) NaOH + NaBr
Acidic	Neutral	Basic
e) $NH_4Br$ + $NH_3$ ($pK_a = 9$)
Acidic	Neutral	Basic

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CHE 112 - Bonus Assignment
Acid/Base and Equilibrium
(Due Aug 08, 12:20 PM)
Name:
To receive credit for this assignment, one of the learning assistants for this course should sign at right to
indicate that you worked through this assignment with them.
1. (8 pts) Explain why silver oxalate (Ag2C2O4, Ksp = 5.40 × 10^-12) has a higher molar solubility than silver
chloride (AgCl, Ksp = 1.77 × 10^-10). Show the calculations that back up your explanation.
2. (5 pts) Identify each of the following 1:1 solution mixtures as acidic, basic, or neutral. Circle the
correct choice. No justification is necessary.
a) HF + KF (pKa = 4)
Acidic Neutral Basic
b) H2SO4 + Na(HSO4)
Acidic Neutral Basic
c) KBr + NaBr
Acidic Neutral Basic
d) NaOH + NaBr
Acidic Neutral Basic
e) NH4Br + NH3 (pKa = 9)
Acidic Neutral Basic

Added by Lori L.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Ronald Prasad

09/01/2020

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To determine the molar solubility, we need to set up an ICE table for the dissolution of the compound. Show more…

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CHE 112 - Bonus Assignment Acid/Base and Equilibrium (Due Aug 08, 12:20 PM) Name: To receive credit for this assignment, one of the learning assistants for this course should sign at right to indicate that you worked through this assignment with them. 1. (8 pts) Explain why silver oxalate (Ag$_2$C$_2$O$_4$, K$_{sp}$ = 5.40x10$^{-12}$) has a higher molar solubility than silver chloride (AgCl, K$_{sp}$ = 1.77x10$^{-10}$). Show the calculations that back up your explanation. 2. (5 pts) Identify each of the following 1:1 solution mixtures as acidic, basic, or neutral. Circle the correct choice. No justification is necessary. a) HF + KF (pKa = 4) Acidic Neutral Basic b) H$_2$SO$_4$ + Na(HSO$_4$) Acidic Neutral Basic c) KBr + NaBr Acidic Neutral Basic d) NaOH + NaBr Acidic Neutral Basic e) NH$_4$Br + NH$_3$ (pKa = 9) Acidic Neutral Basic

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00:03 Let's indicate whether the following salts are acidic, basic, or neutral.

00:08 For a, we have strontium nitrate, which will associate to strontium 2 plus and 2 -03 minus.

00:22 There is no hydrolysis that occurs here.

00:24 Strontium is an alkaline earth metal.

00:26 Nitrate is a conjugate of a strong acid, h .n .o3 nitric acid.

00:32 So this will be a neutral salt.

00:34 There is no hydrolysis that takes place.

00:36 For b, we have nh4, c2h3o2.

00:45 This will associate to nh4 plus and c2h3o2 minus.

00:56 And we have nh4, which acts as a weak acid.

01:06 And we have c2h3o2, which acts as a weak base.

01:15 So let's write the appropriate hydrolysis reactions here.

01:19 Nh4 plus h2o, h3o plus, and h33.

01:28 The ka, we can look up, is equal to 5 .6 times 10 to the minus 10.

01:35 And for the week base, c2, h3o2 minus h2 will yield hc2h2, h2, and and oh h minus we have to calculate the kb here and k from the conjugate is 1 .8 times 10 to the negative 5 this would be equal to 5 .6 times 10 to the negative 10 and here because k a is equal the kb this salt is going to be a neutral salt for c we have ch3 nh3 cl which will dissociate to c .h3 nh3 plus and cl minus.

02:42 Cl minus is the conjugate of a strong acid hcl.

02:47 Ch3 and h3 plus is a weak acid and it will undergo hydrolysis like so.

03:05 And because of this, this salt is going to be an acidic salt.

03:15 For d, we have c6h5 nh3 clo2...

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