00:01
All right, so for question one, we want to write the equilibrium constant expressions.
00:04
So it's just going to be a ratio of the product concentrations to their coefficients divided by the reacting concentrations to their coefficients.
00:11
For part one, we have the products are h plus, and we're going to raise that to its power, which is 2, and then co3 to minus raise to the first power, divided by the concentration of h2, co3.
00:30
And then that's all we need to do.
00:33
For number two, our product is h -i.
00:41
We're going to raise that to the second power, and then we have h -2 and i -2, each to the first power in the denominator from the reactants.
00:53
All right, for part three, everything is to the first power.
01:01
So we have h -c -l concentration and h -o -c -l on the top.
01:09
And then on the bottom, h2o plus cl2.
01:13
Now, h2o is normally omitted because you omit solids and liquids, but in this particular reaction, it's written as aqueous, so i guess they want us to include it because you include aqueous and gaseous species.
01:26
And lastly, for number four, we have no raised to the second power, and then i don't know why it says 2no again.
01:42
Oh, that's an no2, there we go.
01:44
So no squared and then 02.
01:50
For number two, first we want to write an expression for the equilibrium constant given for part one.
01:59
So kc is going to be the same thing that we were doing before.
02:05
The product concentration raised to its coefficient divided by the reacting concentrations raised to their coefficients.
02:18
And then we want to derive its units.
02:20
Well, k is normally dimensionless.
02:22
But if you wanted to find like i guess the ratio of molarities if you have a concentration squared then it's going to be molar squared on the top and then this is molar squared times molar so it's simplified to molar squared over molar cubed which is one over molar you can write that as molar to the negative one or liters over moles because molar to the negative one is an inverse molar so you flip the units.
02:53
All right, for part two, we are given the concentrations, so we want to calculate kc.
02:58
So kc, we can plug in.
03:01
So we want s .o3 on the top.
03:04
We know that one cubic decimeter is equal to one liter, so those are all molar concentrations, which is good.
03:11
So we have 1 .3 squared divided by 1 squared times 0 .2...