00:01
Now first let us see what percentage of the offspring would have featherless shank genes.
00:32
Now let's cross in c.
00:37
So there's a, a, b, crossed with homozygous recessive and heterozygous dominant.
00:52
So we see that in the first generation, or the fn generation, there's formation of heterozygous dominant condition.
01:06
Now when there is crossing over between the same gametes, i say a, b, b, crossing over with a a, heterozycous dominance, let's see in the form of a pannid square.
01:29
Now after pannet square let us see how many of the 16 are featherless birds.
01:36
So if we see here this is featherless, first one this is featherless again so two these two are featherless again three and four this is featherless again five and these two are featherless again six and seven so out of the 16 offspring formed seven of them can be featherless so seven out of 16 are featherless and and this will make up to a percentage of about 43 .75%, which is the answer for question 1 in the or the first part...