00:01
Okay, so here we have two ways to produce chromium metal from chromium -3 oxide.
00:08
And we want to know that grams of aluminum required to prepare a certain amount of chromium metal and the amount of silicon required to repair the same amount.
00:16
So we're starting with 289 .0 grams of chromium for each of these calculations.
00:24
And so we want to do is go from grams of chromium into grams of the other metal that we're using.
00:31
Silicon.
00:33
So first if we're doing aluminum, whenever we're doing a stoichiometric calculation like this, be it's typically easiest to convert everything into moles first so that we can relate the equation to the balanced equation ratios.
00:49
So this is the coefficients in the balanced equation.
00:52
So first we'll need to know chromium, smaller mass.
01:00
So one mole of chromium is equivalent to 51 .9 996 grams.
01:10
And then if we're looking at, first we want to know how much aluminum we need, we can look at the balanced equation and see that two moles of chromium are equivalent to two moles of aluminum.
01:19
So that allows us to convert between things in our equation.
01:25
So now we can go from chromium into units of aluminum.
01:28
And then lastly, we want to know how many grams of aluminum are needed...