Question
Chromium metal can be produced from high-temperature reactions of chromium(III) oxide with silicon or aluminum:$$\begin{aligned}\mathrm{Cr}_{2} \mathrm{O}_{3}(s)+2 \mathrm{Al}(\ell) & \rightarrow 2 \mathrm{Cr(\ell)+\mathrm{Al}_{2} \mathrm{O}_{3}(s) \\2 \mathrm{Cr}_{2} \mathrm{O}_{3}(s)+3 \mathrm{Si}(\ell) & \rightarrow 4 \mathrm{Cr}(\ell)+3\mathrm{SiO}_{2}(s)\end{aligned}$$a. Calculate the mass of aluminum required to prepare 400.0 grams of chromium metal by the first reaction.b. Calculate the mass of silicon required to prepare 400.0 grams of chromium metal by the second reaction.
Step 1
We know that the molar mass of chromium is 52 g/mol. So, we have: $$\frac{400 \, \text{g}}{52 \, \text{g/mol}} = 7.69 \, \text{mol} \, \text{Cr}$$ Show more…
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Chromium metal can be produced from the high-temperature reaction of $\mathrm{Cr}_{2} \mathrm{O}_{3}$ [chromium(III) oxide] with silicon or aluminum by each of the following reactions:$$\begin{aligned} \mathrm{Cr}_{2} \mathrm{O}_{3}(s)+2 \mathrm{Al}(\ell) & \rightarrow 2 \mathrm{Cr}(\ell)+\mathrm{Al}_{2} \mathrm{O}_{3}(s) \\2 \mathrm{Cr}_{2} \mathrm{O}_{3}(s)+3 \mathrm{Si}(\ell) & \rightarrow 4 \mathrm{Cr}(\ell)+3 \mathrm{SiO}_{2}(s)\end{aligned}$$.a. Calculate the number of grams of aluminum required to prepare $400.0 \mathrm{g}$ of chromium metal by the first reaction. b. Calculate the number of grams of silicon required to prepare $400.0 \mathrm{g}$ of chromium metal by the second reaction.
Chromium metal can be produced from the high temperature reaction Cr2O3 (chromium oxide) with silicon or aluminum by each of the following reactions: Cr2O3 + 2 Al -> 2 Cr + Al2O3 2 Cr2O3 + 3 Si -> 4 Cr + 3 SiO2 Calculate the number of grams of aluminum required to prepare 289.0g of chromium metal by the first reaction. Calculate the number of grams of silicon required to prepare 289.0g of chromium metal by the second reaction.
Chromium metal can be produced from the high temperature reaction of Cr2O3 [chromium(III) oxide] with silicon or aluminum by each of the following reactions: Cr2O3 + 2 Al -> 2 Cr + Al2O3 2 CrO3 + 3 Si -> 4 Cr + 3 SiO2 1. Calculate the number of grams of aluminum required to prepare 89.00 g of chromium metal by the first reaction. 2. Calculate the number of grams of silicon required to prepare 89.00 g of chromium metal by the second reaction.
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