Circle the best answer to the following
1- The condition of the missing orders for double slit occurs when
a) The maximum of the interference and the minimum of diffraction are both fulfilled for the same value of angle (θ).
b) The maximum of the interference and the maximum of diffraction are both fulfilled for the same value of angle (θ).
c) The minimum of the interference and the minimum of diffraction are both fulfilled for the same value of angle (θ).
d) The maximum of the interference and the minimum of diffraction are both fulfilled for the same value of different angle (θ).
2) In Fraunhofer diffraction pattern due to a single slit the screen is at a distance of 100 cm from the slit and the slit is illuminated by monochromatic light of wave length 5893 A⁰ the width of the slit is 0.1 mm . Calculate the sepration between the central maximum and the first secondary minimum.
The equation to calculate the separation is
a) x= mfλ/b b) x = mf/λ b c) x= f/mbλ
and the separation is
a) x= 0.4458 cm b) x = 0.5893 cm c) x= 0.6674 cm
3) Deduce the missing orders for a double slit Franhover diffraction pattern if the slit widths are 0.16 mm and they are 0.8 mm a part .
the missing orders are
a) 3 , 6 , 9 .... b) 4 , 8 , 12 ...... c) 6 , 12 , 18 ....
3) Light is incident normally on a grating 0.5 cm wide with 2500 lines. Find the angles of diffraction for the principal maxima of the two sodium lines in the first order spectrum λ₁ =5890 A⁰ , λ₂ =5896 A⁰ .
(i) The formula to find the angles of diffraction is
a) d sin (θ) = m λ b) d cos (θ) = m λ c) d/λ = m sin(θ)
(ii) The angles of diffraction are
a) θ₁ = 15.3⁰ and θ₂ = 14.7⁰ b) θ₁ = 17.1⁰ and θ₂ = 17.2⁰
c) θ₁ = 16.3⁰ and θ₂ = 12.7⁰