00:01
Hello students, let us have a look on this question.
00:02
So, in this question we have given the wavelength of the light lambda is equal to 610 nanometer or we can say 610 into 10 raise to the power minus of 9 meter.
00:13
Now, we have given the slit width also l is equal to 5 meter and distance between the slit and the we can say screen it is equal to capital d equal to 2 into 10 raise to the power minus of 6 meter or we have given the d small d is equal to 12 into 10 raise to the power minus of 6 meter.
00:30
Now, we have to find the width of the central maxima found by the single slit diffraction and we know the formula for this simply is equal to 2 lambda l by d.
00:38
Moving on the formula value of lambda is equal to 610 into 10 raise to the power minus of 9 multiply with the l is equal to 5 and divide by capital d is equal to 2 into 10 raise to the power minus of 6.
00:49
Just solve this value finally, we will have the w c is equal to 3 .05 meter.
00:56
This is equal to w c.
00:58
Moving on one more thing that the question number b this was the question number a.
01:02
Now, moving on the question number b where we have to find location of the first two double slit maxima on the both sides of the central maxima.
01:10
So, it has a formula of y is equal to l lambda l divided by d...