00:01
So in this problem, we are given two different reactions and we're asked to identify the mechanism by which they actually occur.
00:09
So first we have this alcohol and we are adding hcl.
00:13
The first step is that a lone pair will come in and engage in nucleophilic attack that will cause heterotypic cleavage of this hcl.
00:26
Single bond, which will form this positively charged group h2o, and this happens fairly quickly.
00:46
However, the next step is that notice we have this protonated hydroxyl group, it can act as a leaving group.
00:55
So it can simply dissociate and form, once it falls off, that causes the formation, of a carbocadion.
01:07
So where that protonated hydroxyl group once was is now a carbocation.
01:13
Finally, this reacts with a nucleophile.
01:17
In fact, we're going to use the halide or chloride anion that we had formed in our first step.
01:26
This is negatively charged.
01:27
It's going to come in and replace that hydroxyl group.
01:33
So this finally yields us our products.
01:38
Which is given right here.
01:44
Instead of a hydroxyl group, we now have a chlorine atom and we also have water...