00:01
Okay.
00:05
So we have got, okay, and we've got an equilibrium like so.
00:43
And the question then is for us to use an arrow to show which direction the equilibrium lies.
00:55
Okay.
00:59
Well, which of these is acting as the acid in each case? you're right.
01:02
This is acting as an acid in one case, and this is acting as an acid in the other case.
01:07
Okay very good but i think you got the pca swapped the pca of this acid is around and the pca of this acid is around 45 right which means this is the much stronger acid right so the stronger acid being on the left means that the equilibrium arrow should favor the right hand side so this is what our equilibrium should look like right this acid is 10 to the 20 times as strong as this acid.
01:40
So if anyone's getting deprotinated, it's this acid.
01:45
So i think you just flip -flopped the pkk's.
01:48
It's going to favor the right.
01:53
Okay, now let's use curvy arrows to show the movement of electrons, circle the strongest base in the reaction, and give the approximate ratio of reactors to products of the equilibrium in this reaction.
02:04
So curvy arrows, this lone pair attacks this hydrogen, and the carbon -hydrogen bond electrons remain on carbon.
02:12
And then if i want to do that over here...