00:01
So based on the question, we are to complete the following reaction and write the iopac names of the two products.
00:08
Of the two products.
00:10
Okay.
00:10
So when an ester is hydrolyzing the presence of a base, that is an n -a -o -h, the reaction is called a subonification reaction, supponification reaction.
00:22
And this is because we know the hydrolysis of oils, fats, and alkaline hydrolysis of estes give carbon.
00:30
Oxalate salt and alcohol as product.
00:34
So the reaction can be given below as this.
00:38
So let's look at the reaction.
00:41
We have ch3.
00:48
We have ch3, ch2, ch2, ch2, ch2, ch2.
01:12
Then we have a c double bonded to oxygen so bonded to the oxygen here and we have c h 3 plus n a -o -h n -a -o -h going to where in the presence of h2o in the presence of h2o in the presence of of h2.
02:01
Now we have here the metal hexanoids.
02:09
So we have the metal hexanoids.
02:14
So we have the metal hexanoids.
02:22
That's the ester...