00:01
Hello students, in this question they have asked to complete this given table.
00:05
Here they have given the final concentration c2 of glucose in varying concentrations here and next they have asked to list the v1 concentration here and they have given that the value of c1 is 50 millimolar and next here also they have asked to find the value of v2 -v1 and they have given the final volume v2 here.
00:35
The equation for finding this value is c1 -v1 is equals to c2 -v2.
00:43
First we have to find the value of v1 that is v1 is equals to c2 -v2 divided by c1.
00:53
So here for the first concentration that is the value of c2 is equals to 5 millimolar and the value of c1 is given as 50 millimolar and the value of v2 is given as 5.
01:09
So the value of v1 is equals to 5 into 5 that is c2 into v2 divided by the value of c1 which is given as 50 here.
01:24
This gives the value of 25 divided by 50 which is equals to 0 .5 ml and the v2 -v1 that is 5 -0 .5 is equals to 4 .5 ml.
01:44
So we have to add 4 .5 ml distilled water and the v1 value is 0 .5 here.
01:54
Next similarly the v1 is equals to c2 value which is given as 10 multiplied with a v2 value which is given as 5 divided by 50 which is the c1 value.
02:06
This gives the value of 50 by 50 which is equals to 1 ml.
02:14
So here v2 -v1 is equals to v2 which is given as 5 -v1 which is given as 1...