Find the value of the integral \( \int_c \frac{dz}{z^3(z+4)}, \) taken counterclockwise around the circle (a) \(|z| = 2\); (b) \(|z + 2| = 3\). Ans. (a) \(\frac{\pi i}{32}\); (b) 0.
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Step 1: First, let's factor the denominator z^3(z+4) as z^3 * (z+4). Show more…
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