Compounding interest: If $3,500 is invested at a rate of 6.23% per year, compounded continuously, find the value of the investment after the given number of years.
G(t) = -3t + 1
H(t) = 2t + 5
Find (g h)(t)
F(n) = n^3 + 2
G(n) = -4n + 4
Find (2f + g)(n)
F(t) = t - 5
G(t) = -t^2 + 5
Find (4f + 4g)(t)
F(x) = -x + 3
G(x) = 3x - 3
Find (4t - 4g)(x)