Compute area of the region bounded by $y = 3x^2 - 4x$ and $y = 2x$. The figure below gion(shaded) and coordinates of the intersection points of the two curves. $y$ $(2, 4)$ $x$ $-1$ $-0.5 (0, 0)$ $0.5$ $1$ $1.5$ $2$ $2.5$ $3$ $-1$ $1$ $2$ $3$ $4$ $5$
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Set the two equations equal to each other: $3x^2 - 4x = 2x$ $3x^2 - 6x = 0$ Factor out $3x$: $3x(x - 2) = 0$ This gives two solutions for $x$: $3x = 0 \Rightarrow x = 0$ $x - 2 = 0 \Rightarrow x = 2$ Now, find the corresponding $y$ values for these $x$ values Show more…
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