Step 1:
For the first limit, we can divide both numerator and denominator by $x^2$ to get:
$$\lim_{x \to \infty} \frac{1+sin^2(x)}{(1+\frac{sin(x)}{x})^2}$$
Since $-1 \le sin(x) \le 1$, we have:
$$\lim_{x \to \infty} \frac{sin(x)}{x} = 0$$
Therefore, the limit
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