We have
$$ L = \lim_{(x,y)\to(0,0)} \frac{x^3y^2 + 2y^3}{x^3 + y^3} $$
Let us approach $(0,0)$ along the path $y = mx$. Then
\begin{align*} \label{eq:1} L &= \lim_{x\to 0} \frac{x^3(mx)^2 + 2(mx)^3}{x^3 + (mx)^3} \\ &= \lim_{x\to 0} \frac{m^2x^5 + 2m^3x^3}{x^3(1 +
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