Question

Compute: $z = \sqrt{y - x}$ Ex. If the input is 3.0 4.0, then the output is: 1.0 1 import java.util.Scanner; 2 3 public class MathFunctions { 4 public static void main (String[] args) { 5 Scanner scnr = new Scanner(System.in); 6 double x; 7 double y; 8 double z; 9 10 x = scnr.nextDouble(); 11 y = scnr.nextDouble(); 12 13 // Your code goes here // 14 15 System.out.printf(".1f\n", z); // This will output z with 1 decimal place. 16 } 17}

          Compute: $z = \sqrt{y - x}$
Ex. If the input is 3.0 4.0, then the output is:
1.0
1 import java.util.Scanner;
2
3 public class MathFunctions {
4	public static void main (String[] args) {
5		Scanner scnr = new Scanner(System.in);
6		double x;
7		double y;
8		double z;
9
10		x = scnr.nextDouble();
11		y = scnr.nextDouble();
12
13		// Your code goes here //
14
15		System.out.printf(".1f\n", z); // This will output z with 1 decimal place.
16	}
17}

Compute: z = √(y - x)
Ex. If the input is 3.0 4.0, then the output is:
1.0
1 import java.util.Scanner;
2
3 public class MathFunctions
4 public static void main (String[] args)
5 Scanner scnr = new Scanner(System.in);
6 double x;
7 double y;
8 double z;
9
10 x = scnr.nextDouble();
11 y = scnr.nextDouble();
12
13 // Your code goes here //
14
15 System.out.printf(".1f", z); // This will output z with 1 decimal place.
16
17

Added by Amanda C.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Ct Turner

Step 1

First, we need to compute z = sqrt(y - x). Show more…

Show all steps

Thanks for your feedback!

Compute: z = sqrt(y - x) Start Compute z = y - x Ex: If the input is 3.0 and 4.0, then the output is 1.0. import java.util.Scanner; public class MathFunctions { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); double x, y, z; x = scnr.nextDouble(); y = scnr.nextDouble(); // Your code goes here System.out.printf("%.1f", z); // This will output z with one decimal place. } }