00:01
In the question it is given that given that r vector of t is equal to 9t cube plus 2t square plus 5t plus 10, 10t cube plus 5t square plus 9t plus 6, 3t cube plus 8t square plus 11t plus 9 where t is less than or equal to 2 but greater than or equal to 0.
00:45
Now let r vector of 1 is equal to a, b so we have to find, we have to find a, b and c.
01:07
So we have the condition that is t is less than or equal to 2 but greater than or equal to 0 so that means we have t is equal to 1.
01:17
That is why we have taken r vector of 1 is equal to a, b, c.
01:22
Now we will find a, b and c.
01:24
So we have a is equal to 9t cube plus 2t square plus 5t plus 10.
01:34
So we will put t is equal to 1 in the above equation.
01:39
So 1 will become 9 multiplied by 1 cube plus 2 multiplied by 1 square plus 5 multiplied by 1 plus 10.
01:48
So a will be equal to 9 plus 2 plus 5 plus 10 which is equal to 26.
01:58
Now we will find b.
02:00
So we have b is equal to 10t cube plus 5t square plus 9t plus 6...