Question

Consider a 40 kVA, 8000V/240V, 60 Hz transformer has the following parameters $R_{C,LV} = 164 \Omega$ $X_{M,LV} = 44.6 \Omega$ $R_{eq,HV} = 50.4 \Omega$ $X_{eq,HV} = 212 \Omega$ LV - referred to Low Voltage Side HV - referred to High Voltage Side Determine the values of these parameters in the per-unit system.

          Consider a 40 kVA, 8000V/240V, 60 Hz transformer has the following parameters
$R_{C,LV} = 164 \Omega$
$X_{M,LV} = 44.6 \Omega$
$R_{eq,HV} = 50.4 \Omega$
$X_{eq,HV} = 212 \Omega$
LV - referred to Low Voltage Side
HV - referred to High Voltage Side
Determine the values of these parameters in the per-unit system.

Consider a 40 kVA, 8000V/240V, 60 Hz transformer has the following parameters
RC,LV = 164 Ω
XM,LV = 44.6 Ω
Req,HV = 50.4 Ω
Xeq,HV = 212 Ω
LV - referred to Low Voltage Side
HV - referred to High Voltage Side
Determine the values of these parameters in the per-unit system.

Added by Eugenia H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Darshan Maheshwari

Step 1

The base power (Sbase) is given as 40 kVA. The base voltage on the low voltage side (Vbase,LV) is given as 240V. The base current on the low voltage side (Ibase,LV) can be calculated using the formula: Ibase,LV = Sbase / Vbase,LV Ibase,LV = 40,000 VA / Show more…

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Consider a 40 kVA, 8000V/240V, 60 Hz transformer that has the following parameters: RcLV = 1649, XMCv = 44.69, Req-HV = 50.49, Xeq,HV = 212 Q. LV refers to the Low Voltage Side and HV refers to the High Voltage Side. Determine the values of these parameters in the per-unit system.