Consider a binomial distribution of 200 trials with expected value 80 and standard deviation of about 6.9. Use the criterion that it is unusual to have data values more than 2.5 standard deviations above the mean or 2.5 standard deviations below the mean to answer the following questions. (a) Would it be unusual to have more than 120 successes out of 200 trials? Explain.
Added by Raymond B.
Step 1
Given that $n = 200$ and the expected value is 80, we can find $p$ by dividing the expected value by the number of trials: $p = \frac{80}{200} = 0.4$. Now, calculate the standard deviation: $\sigma = \sqrt{200 \cdot 0.4 \cdot (1-0.4)} = \sqrt{48} \approx Show more…
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Consider a binomial distribution of 200 trials with expected value 80 and standard deviation of about $6.9 .$ Use the criterion that it is unusual to have data values more than 2.5 standard deviations above the mean or 2.5 standard deviations below the mean to answer the following questions. (a) Would it be unusual to have more than 120 successes out of 200 trials? Explain. (b) Would it be unusual to have fewer than 40 successes out of 200 trials? Explain. (c) Would it be unusual to have from 70 to 90 successes out of 200 trials? Explain.
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Consider a binomial distribution of 200 trials with expected value 80 and standard deviation of about $6.9 .$ Use the criterion that it is unusual to have data values more than $2.5$ standard deviations above the mean or $2.5$ standard deviations below the mean to answer the following questions. (a) Would it be unusual to have more than 120 successes out of 200 trials? Explain. (b) Would it be unusual to have fewer than 40 successes out of 200 trials? Explain. (c) Would it be unusual to have from 70 to 90 successes out of 200 trials? Explain.
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