Consider a box with dimensions 3 cm × 5 cm × 11 cm. If all of its dimensions are increased by x cm, what values of x will give a box with a volume between 300 cm3 and 900 cm3? [6 marks]
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The volume \( V \) of a box is given by the formula: \[ V = \text{length} \times \text{width} \times \text{height} \] For the box with dimensions 3 cm, 5 cm, and 11 cm: \[ V = 3 \times 5 \times 11 = 165 \, \text{cm}^3 \] Show more…
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Consider a box with dimensions 3 cm × 5 cm × 11 cm. If all of its dimensions are increased by x cm, what values of x will give a box with a volume between 300 cm3 and 900 cm3?
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Consider a box with the dimension 3 cm x 5 cm x 11 cm. If all the dimensions are increased by x cm, what values of x will give a box with a volume between 300cm^2 and 900 cm^2. I got up until x^2+19x^2+103x+165 but not sure to go from there. Im also not sure if long division is needed but I cannot find the factor for long division through systematic guessing.
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