00:01
And this question, you look at a particle of one dimension, infinite square wall.
00:04
And the eigenstates for this potential given in the question, right? let me just write it down.
00:10
So x equals square over two over here.
00:16
Sorry, air.
00:18
Air is the length of the wire, right? corsin.
00:22
And pi x over l for m out.
00:29
And squalots of two over air, sign pi n x over l for n even.
00:39
You are asked two questions.
00:41
First is, should that to the first order, well, now you add an additional potential, which is vx, probation, probative potential, right? which is lv0 data x.
00:55
Now you're asked to show that to the first order in v0, the energies of the end, the aught, does not.
01:03
Not increased, okay, about a little bit, but the energy, the n, even if there's a non -changed, you know, the energy correction to a particular state, it's given by vx to the first order side n squared and from minus a .o .2, air over two, right? the integration is down over the way, the potential way, right? now, vx is a data function, direct data function, is pretty easy...