00:01
In this question it is considered a container with a square base where the dimensions are given by x, x and y is the height.
00:17
Now, it is also given that the volume of the containers would be 70 cubic centimeters.
00:23
So we have volume b to be equal to x square y equals to 70.
00:29
So from this we can say that y is equal to 70.
00:33
By x squared.
00:35
Now let us consider the cost function c of x so it will be 2x2 x times of 0 .40 as it is costing 0 .40 per centimeter square for the top and the bottom plus for the sides it is costing 0 .20 per centimeter square so the sides will be 4 xxx times of 0 .20 on adding these to so we will get the cost function.
01:05
Now, c of x is equal to, we will multiply these two.
01:10
So we have 0 .8 x squared plus 0 .8 x times off.
01:15
In the place of why, let us put 70 by x square.
01:18
So we have 70 by x square.
01:21
So therefore, our function, c of x is equal to 0 .8x square plus 56 by x.
01:29
Now, this is the cost function.
01:31
Let us now differentiate this...