00:01
Consider points a 2, 3, 4 and b 0, 1, 2 and c -1, 2, 0.
00:11
Find the area of the parallelogram abcd with adjacent sides ab and ac.
00:17
Find the area of the triangle abc.
00:19
Find the distance from point b to line ac.
00:24
Given ab and c, ab will be equals to b -a which is (-2, 4, 2).
00:36
And ac will be c -a which is (-3, 5, 4).
00:43
So then the area of the parallelogram would be ab times ac and ab times ac would be equals to what have ijk (-2, 3, 4, 5), (-2, 4).
01:03
So this should be 4, 5, (-2, 4), i, minus, (-2, 2), (-3, 4), j, plus, (-2, 3), 4, 5 and k.
01:22
So this should be minus 6i, minus 2j, plus 2k.
01:27
So then the absolute of ab times ac would be equals to the square root of minus 6 squared, plus minus 2 squared, plus 2 squared...