00:01
So we know that a of t is the amount of die in the tank at time t.
00:07
So a prime is going to be the rate in minus the rate out.
00:13
So then what we end up getting is the rate in is zero because even though water is coming in, it doesn't have any dye.
00:21
So that's going to be a prime equals zero minus the rate out is going to be a.
00:32
That's the amount over 200 because that's how many liters of a dye solution are in, and it contains 1 gram per liter.
00:43
So it's a over 100.
00:45
And then we know that it's flowing in, or it's flowing out at a rate of 2 liters per minute.
00:53
So it's flowing out at 2 liters per minute.
00:56
So this ends up giving us a prime equals a negative 1 over 100a.
01:02
But now we can integrate on both sides.
01:14
So we see that if we move the a of t function over, we end up getting a prime over a equals negative 1 over 100.
01:28
So this gives us, we integrate on both sides, log of a plus c1 equals negative t over 100.
01:40
Plus c2...