00:01
Hello students, according to the given question we have to find out the chi -square test.
00:06
So it was given the data in the a bit we have to find the expected frequency of this cell i comma j so the formula will be equal to row sum value of i into column sum that is j divided by 100.
00:31
So now the expected frequency table for the given data will be according to above formula we get let it be a1 a2 and a3 here let it be b1 and b2 so here the value is 12 18 30 8 12 and 20.
00:58
So now the chi -square formula will be chi -square is equal to summation o i minus ei whole square is divided by ei.
01:09
So according to the given data by substituting we get 0 .68055.
01:16
So now p value will be equal to 0 .715 which is greater than alpha that is 0 .10.
01:27
So in this case the conclusion is we fail to reject the we fail to reject the null hypothesis that is h naught and conclude and conclude that there will be an independence.
01:49
Now in the b bit here we have to assume the sample size n value as 1000.
01:56
So in this case the expected frequency of this cell i j i comma j will be equal to row sum that is of i into column sum that is j divided by here total n value is 1000.
02:25
So then here the expected frequency table will be for the given data it is 120 180 300 80 120 and 200...