00:01
So we have four capacitors set up here, something like this, and the batteries here.
00:16
So this is going to be c1, c2, c3, c4, and the same goes for q1, q2, q3, q4, and all the voltages.
00:28
I'll keep the same subscripts.
00:30
So for the equivalent capacitance, first of all, we can just add c2 and c3.
00:36
Let me get eight, no, six plus two, which gives us total of eight.
00:47
Okay, so now we have something that looks like this with just three capacitors in series where this is this whole thing combined as a unit, right? so now to find the equivalent capacitance, each of these are all eight microfraeric capacitors.
01:17
This is .375, and you take the reciprocal.
01:22
You get the equivalent capacitance is 2 .67 microferds.
01:27
Now we have enough information to start figuring out the charges.
01:32
So q1 is just going to be the equivalent capacitance times the voltage, because we have these three capacitors in series, so the charge is going to be the same.
01:49
And this is 2 .67 times 9 volts.
01:55
Which gives us 24 micro -coolums.
02:00
And this is the same for q4 with the same capacitance.
02:07
It's also the same for the middle capacitor in the second drawing, which is actually q2 plus q3.
02:14
So we don't know exactly what each of those individually are yet until we figure out the voltages.
02:24
So v1, the potential difference across the first capacitor, it's going to be q1 over c1, which is 24 microculomes over 8 microferds, which gives us 3 volts.
02:51
And the same is true for v2 and v3 and v4.
03:02
Because, well, v4 has the same capacitance as the first capacitance...