Consider the balanced chemical reaction below:
2K2O(aq) + Sn(NO3) 4(aq) → 4KNO3(aq) + SnO2(s)
When 10.25 g of K2O is mixed with 19.75 g of Sn(NO3)4, 7.6942 g of SnO2 is obtained. What reactant is
the limiting reactant? What is the percent yield?
OK2O is the limiting reactant. The percent yield is 46.9%
K2O is the limiting reactant. The percent yield is 93.8%.
Sn(NO3) 4 is the limiting reactant. The percent yield is
39.0%
Sn(NO3) 4 is the limiting reactant. The percent yield is
5.20%.
Sn(NO3)4 is the limiting reactant. The percent yield is
94.8%.
Molar Mass
(g/mol)
Compound
K2O
94.196
Sn(NO3)4
366.7296
KNO3
101.1032
SnO2
150.7088
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