Question

Consider the Bode plot: Bode Diagrams Phase (deg); Magnitude (dB) Which transfer function H(s) corresponds to the Bode plot? \( H(s) = \frac{24}{s(s+2)(s+6)} \) \( H(s) = \frac{100}{s(s+5)(s+6)} \) \( H(s) = \frac{10}{s^2 + 0.5s + 10} \) \( H(s) = \frac{24}{s^2(s+6)} \)

          Consider the Bode plot:
Bode Diagrams
Phase (deg); Magnitude (dB)
Which transfer function H(s) corresponds to the Bode plot?
\( H(s) = \frac{24}{s(s+2)(s+6)} \)
\( H(s) = \frac{100}{s(s+5)(s+6)} \)
\( H(s) = \frac{10}{s^2 + 0.5s + 10} \)
\( H(s) = \frac{24}{s^2(s+6)} \)

Consider the Bode plot:
Bode Diagrams
Phase (deg); Magnitude (dB)
Which transfer function H(s) corresponds to the Bode plot?
H(s) = (24)/(s(s+2)(s+6))
H(s) = (100)/(s(s+5)(s+6))
H(s) = (10)/(s^2 + 0.5s + 10)
H(s) = (24)/(s^2(s+6))

Added by Aimee M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ajay Singhal

Step 1

We can see that the magnitude starts at -100 dB and decreases as the frequency increases. This indicates a high-pass filter behavior. Looking at the options, the only transfer function that represents a high-pass filter is OH(s) = 24s(s+2s+6). Now, let's analyze Show more…

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Consider the Bode plot: Bode Diagrams 50 0 ......... -50 Phase (deg); Magnitude (dB) -100 0 -50 -100 -150 -200 -250 -300 102 101 10 101 102 Frequency (rad/sec) Which transfer function H(s) corresponds to the Bode plot? OH(s) = 24s(s+2s+6) OH(s) = 100(g+s)(+s)s OH(s) = 10s^2+0.5s+10 OH(s) = 24s^2(s+6)