00:01
Okay, we're giving this circuit.
00:02
You want to use the mesh current method to find the power and the 10k resistor.
00:08
So let's define our mesh currents like that.
00:22
All right, and then because of this, because that current source, we have that i -1 is 25 million amps.
00:35
And then we get two loops for i -2 and i -3.
00:42
So we use the voltage law on these.
00:52
This has 20 volts, 90k, i2, minus 2k, i2 minus i1, minus 4k, i2 minus i3, and then loop 3.
01:20
We don't get a loop 1 because of the current source.
01:25
And then we got minus 10k3.
01:55
All right...