Consider the circuit in (Figure 1). Figure 12 ? 12 V 20 ? 30...

Consider the circuit in (Figure 1). Figure 12 ? 12 V 20 ? 30 ? Part A Find the current through the 12 ? resistor. Express your answer with the appropriate units. I_{12 ?} = Value Units Submit Request Answer Part B Find the potential difference across the 12 ? resistor. Express your answer with the appropriate units. ?V_{12 ?} = Value Units Submit Request Answer

Transcript

00:01 Hello students, here is the circuit diagram given in the portion.

00:05 Now here is the r1 resistance, r2 and r3 resistance given.

00:11 Now if current is there in this direction, then i1 flows in this direction and i2 flows in this direction.

00:20 Now as we seen that resistance r2 and r3 are connected in parallel.

00:29 So we can find the equivalent resistance and the formula for this will be equivalent resistance 1 upon r2 plus 1 upon r3.

00:43 Now both resistance are connected in parallel so we can write 1 upon 20 plus 1 upon 30.

00:50 So after solving we get equivalent resistance will be 60 by 5 or this can be 12 ohm.

01:00 Now we see that the r equivalent this and r1 resistance are connected in these are connected with r1, r in series.

01:16 So for series we can find effective resistance.

01:19 So effective resistance in this case will be here we got 12 ohm and r1 is 12 ohm.

01:26 So effective resistance will be 24 ohm.

01:31 Now next we can find the current through circuit.

01:42 So the current through circuit we can find by the relation i is equal to v upon effective resistance.

01:50 Now here i is the current, v is the voltage and r here is the resistance or the effective resistance.

01:57 Now we can substitute the values here.

01:59 So we have given 12 volt upon equivalent resistance will be 24.

02:05 Now from here we find the current is 0 .5 ampere.

02:12 Now current through 12 ohm resistance.

02:23 So current through 12 ohm resistance will be i, current for 12 ohm we find 0 .5 ampere.

02:34 Now we can find voltage across 2 ohm resistance.

02:38 So this will be equal to current into resistance.

02:42 So we find 0 .5 into 12...

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