Question

Consider the circuit of Fig. $\mathrm{P} 6.49$ for the case $V_{B B}=V_{C C} .$ If the $\mathrm{BJT}$ is saturated, use the equivalent circuit of Fig. 6.20 to derive an expression for $\beta_{\text {forced }}$ in terms of $V_{C C}$ and $\left(R_{B} / R_{C}\right) .$ Also derive an expression for the total power dissipated in the circuit. For $V_{C C}=5 \mathrm{V}$ design the circuit to obtain operation at a forced $\beta$ as close to 10 as possible while limiting the power dissipation to no larger than $20 \mathrm{mW}$. Use $1 \%$ resistors (see Appendix G).

          Consider the circuit of Fig. $\mathrm{P} 6.49$ for the case $V_{B B}=V_{C C} .$ If the $\mathrm{BJT}$ is saturated, use the equivalent circuit of Fig. 6.20 to derive an expression for $\beta_{\text {forced }}$ in terms of $V_{C C}$ and $\left(R_{B} / R_{C}\right) .$ Also derive an expression for the total power dissipated in the circuit. For $V_{C C}=5 \mathrm{V}$ design the circuit to obtain operation at a forced $\beta$ as close to 10 as possible while limiting the power dissipation to no larger than $20 \mathrm{mW}$. Use $1 \%$ resistors (see Appendix G).

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Added by Gabrielle S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Chai Santi

12/08/2021

Step 1

2}{R_C}\) - \(I_B = \frac{V_{CC} - 0.7}{R_B}\) - \(\beta_{forced} = \frac{I_C}{I_B} = \frac{V_{CC} - 0.2}{V_{CC} - 0.7} \times \frac{R_B}{R_C}\) - Total power dissipated: \(P = V_{CC} \times I_C + V_{CC} \times I_B = (V_{CC} - 0.2) \times I_C + (V_{CC} - 0.7) Show more…

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Consider the circuit of Fig. $\mathrm{P} 6.49$ for the case $V_{B B}=V_{C C} .$ If the $\mathrm{BJT}$ is saturated, use the equivalent circuit of Fig. 6.20 to derive an expression for $\beta_{\text {forced }}$ in terms of $V_{C C}$ and $\left(R_{B} / R_{C}\right) .$ Also derive an expression for the total power dissipated in the circuit. For $V_{C C}=5 \mathrm{V}$ design the circuit to obtain operation at a forced $\beta$ as close to 10 as possible while limiting the power dissipation to no larger than $20 \mathrm{mW}$. Use $1 \%$ resistors (see Appendix G).

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