C2 C3 C1 C4 V
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Since C1 and C2 are in series, we can find their equivalent capacitance (Cs1) using the formula: 1/Cs1 = 1/C1 + 1/C2 1/Cs1 = 1/2.3 + 1/4.2 Cs1 = 1.48 µF Now, we have a new circuit with capacitors Cs1, C3, and C4 in parallel. The equivalent capacitance of this Show more…
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