Consider the combination of resistors shown in the figure...

Consider the combination of resistors shown in the figure below: 12.0 Ω 4.00 Ω 5.00 Ω 6.00 Ω 8.00 Ω (a) Find the equivalent resistance between point a and b. (b) If a voltage of 69.2 V is applied between points a and b, find the current in each resistor: 12 Ω 5.93 A 6 Ω 1.97 A 5 Ω 3.96 A 4 Ω 3.95 A 8 Ω 1.98 A

Transcript

00:01 Hello everyone, in this question we have given a circuit diagram.

00:05 We have to find the equivalence resistance and the current in each resistors.

00:12 Here 12 om and 6 om are in parallel.

00:15 Let their equivalence is r1.

00:18 So we can write 1 divided by r1 is equal to 1 divided by 12 plus 1 divided by 6.

00:28 From here we get 1 plus 2 divided by 12.

00:35 This equal to 1 divided by 4.

00:40 So the value of r1 is 4 om.

00:47 Now 4 om and 8 ome are also in parallel.

00:52 So their equivalence, suppose 1 divided by r2 is equal to 1 divided by 4 plus 4 plus 2.

01:00 1 divided by 8.

01:03 This we can write 2 plus 1 divided by 8.

01:08 This equal to 3 divided by 8.

01:13 So r2 will be 8 divided by 3 is equal to 2 .66 om.

01:23 Now r1, r2 and 5 ome processors are in series.

01:30 So the equivalence resistance of the circuit will be r is equal to r1 plus r2 plus 5 on putting the values r1 is 4 om r2 is 2 .66 ome plus 5 on solving this we get 11 .66 ome so this will be the equivalent resistance of the circuit.

02:02 Now the total current in the circuit will be i is equal to v divided by r.

02:09 Here we have given the value of v as 69 .2 volt.

02:16 So on putting the values we get total current in the circuit is 69 .2 divided by 11 .66.

02:28 On solving this we get 5 .9 so the voltage across r1 will be, suppose v1 is equal to i r1, the value of i is 5 .9 and the value of r1 is 4...

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