Question

Consider the data path below for a single cycle 32-bits MIPS processor Assume that we are executing the following instruction ADD $s3, $s0, $s2 What is the value of the element pointed by arrow number 1 by in hexadecimal? Note that the PC and the content of registers are found in bottom left of the figure below Address Content 0x000016EC 0x0000ABOD 0x000016F0 0x00A01245 0x000016F4 0x00001A42 ... 0x000171C 0x000B124F 0x0001720 0x00021345 0x0001724 0x000067AB ... 0x0001734 0x0000AB35 0x0001738 0x0000FA72 0x000174C 0x0000ABOC $s0 = 0x0000AF00 $s2 = 0x000000BA $s3 = 0x00000001 PC = 0x000FAC04 (Before executing ADD) Select one: a. 0x000FAC04 b. 0x000F4428 c. 0x00120C84 d. 0x000FAC08 e. None of the options

          Consider the data path below for a single cycle 32-bits MIPS processor
Assume that we are executing the following instruction
ADD $s3, $s0, $s2
What is the value of the element pointed by arrow number 1 by in hexadecimal?
Note that the PC and the content of registers are found in bottom left of the figure below
Address	Content
0x000016EC	0x0000ABOD
0x000016F0	0x00A01245
0x000016F4	0x00001A42
...
0x000171C	0x000B124F
0x0001720	0x00021345
0x0001724	0x000067AB
...
0x0001734	0x0000AB35
0x0001738	0x0000FA72
0x000174C	0x0000ABOC
$s0 = 0x0000AF00
$s2 = 0x000000BA
$s3 = 0x00000001
PC = 0x000FAC04
(Before executing ADD)
Select one:
a. 0x000FAC04
b. 0x000F4428
c. 0x00120C84
d. 0x000FAC08
e. None of the options

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consider the data path below for a single cycle 32 bits mips processor assume that we are executing the following instruction add s3 s0 s2 what is the value of the element pointed by arrow n 48616

Added by Ashley G.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

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Solved by Expert Umar Sohail Qureshi

01/10/2022

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The arrow points to the address 0x0001720 in the Data Memory section of the figure. Show more…

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Consider the data path below for a single cycle 32-bits MIPS processor Assume that we are executing the following instruction ADD $s3, $s0, $s2 What is the value of the element pointed by arrow number 1 by in hexadecimal? Note that the PC and the content of registers are found in bottom left of the figure below Address Content 0x000016EC 0x0000ABOD 0x000016F0 0x00A01245 0x000016F4 0x00001A42 ... 0x000171C 0x000B124F 0x0001720 0x00021345 0x0001724 0x000067AB ... 0x0001734 0x0000AB35 0x0001738 0x0000FA72 0x000174C 0x0000ABOC $s0 = 0x0000AF00 $s2 = 0x000000BA $s3 = 0x00000001 PC = 0x000FAC04 (Before executing ADD) Select one: a. 0x000FAC04 b. 0x000F4428 c. 0x00120C84 d. 0x000FAC08 e. None of the options

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Transcript

00:01 So here we've got a question about floating point notation.

00:05 I wrote the chart for xs4 notation in the top left.

00:09 So if you see these three bits, if you see there 111, that means we're moving the radix point three spaces to the right.

00:18 If you see 0 -0 -0, that means we're moving the radix point four spaces to the left.

00:24 Okay, but for this first one, let's go ahead and get started with our very first bit.

00:29 0.

00:31 Zero in floating point notation indicates a positive.

00:36 And now for the next three, this is going to be where we move the radix point.

00:41 I'm actually going to skip this for now and go straight on to 1001, our actual value that we're getting out of this.

00:49 1 .001 can go right here, just copied down.

00:53 I'm going to put our radix point right here for now.

00:58 And what does 101 mean? well, if i'm looking at excess notation, 1 -0 -0 is just 0, so 101 is a step above that.

01:07 It's just one space.

01:10 Look what i'm doing to that radix point.

01:12 I'm moving it up one space, positive one space.

01:16 That's going to become positive 1 .001, also known as 1 and 1 8th.

01:32 Let's do one more.

01:34 So this next one, again we're going to split these into chunks.

01:38 First we're going to see that one and say, oh, that's negative.

01:42 Then we're going to skip the middle, go straight to our last four bits.

01:46 One zero, zero, zero...

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