Question

Consider the definite integral $I = \int_1^3 \frac{3x}{\sqrt{x^2+4}} dx$. Using composite Simpson's rule with $n=4$, the approximation of $I$ is 3.426218 2.45182 4.10848 1.82461

Name: consider the definite integral i int13 frac3xsqrtx24 dx using composite simpsons rule with n4 the approximation of i is 3426218 245182 410848 182461 24318
Uploaded: 2023-07-25T17:25:53-08:00
Duration: 1 min 9 s
Channel: Tim Thornhill
Description: consider the definite integral i int13 frac3xsqrtx24 dx using composite simpsons rule with n4 the approximation of i is 3426218 245182 410848 182461 24318

          Consider the definite integral $I = \int_1^3 \frac{3x}{\sqrt{x^2+4}} dx$. Using composite Simpson's rule with $n=4$, the approximation of $I$ is
3.426218
2.45182
4.10848
1.82461

$consider the definite integral i int13 frac3xsqrtx24 dx using composite simpsons rule with n4 the approximation of i is 3426218 245182 410848 182461 24318$

Added by Sarah H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Tim Thornhill

07/25/2023

Step 1

We want to approximate $\int_1^3 f(x) dx$ using composite Simpson's rule with $n=4$. The interval is $[1, 3]$, so $a=1$ and $b=3$. The width of each subinterval is $h = \frac{b-a}{n} = \frac{3-1}{4} = \frac{1}{2} = 0.5$. The points are $x_0 = 1, x_1 = 1.5, x_2 = Show more…

Show all steps

Thanks for your feedback!

Consider the definite integral $I = \int_1^3 \frac{3x}{\sqrt{x^2+4}} dx$. Using composite Simpson's rule with $n=4$, the approximation of $I$ is 3.426218 2.45182 4.10848 1.82461