Consider the equation and the given point. f(x) = (x^3 + 4x - 1)(x - 2), (1, -4) (a) Find an equation of the tangent line to the graph of f at the given point. y =
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To find the derivative, we use the product rule: \[ f(x) = u(x) \cdot v(x) \] where \( u(x) = x^3 + 4x - 1 \) and \( v(x) = x - 2 \). The product rule states: \[ f'(x) = u'(x) \cdot v(x) + u(x) \cdot v'(x) \] First, compute \( u'(x) \) and \( v'(x) \): \[ u'(x) Show more…
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