00:01
In this question it is given that a differential equation of the form where a, b and c are constant.
00:14
So now here it is also given that y1 and y2 will be the solution of this above differential equation and we need to prove that y1 square plus y2 square is not equals to 0.
00:37
That is we need to prove that y1 which is a function of x and the square of it plus y2 which is also a function of x and the square of it is not equals to 0.
00:51
So here for proving it, consider the above differential equation as a y double dash plus b y -dash plus c is equal to 0.
01:07
So here its auxiliary equation will be a, m squared plus b, m plus c is equal to 0.
01:20
So here the roots will be determined by a formula as m is equals to negative b, positive negative, b squared negative 4ac divided by 2a.
01:36
So here this b is the coefficient of b so here it will be b only.
01:46
This a is the coefficient of m square.
01:51
So here a will be a only and c is a constant so here c will be c only...