Consider the following differential equation ÿ + 5 ? + 6 y = 12e^-4t + 6t , y(0) = -1 , ?(0) = 0 . The general solution is a. 35e^-2t + 41e^-3t + 12e^-4t + t - 5/6 b. -41e^-2t - 35e^-3t - 6e^-4t + t - 5/6 c. -41e^-2t + 35e^-3t + 6e^-4t + t - 5/6 d. -41e^2t + 35e^3t + 12e^-4t + t + 5/6
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This is a linear, homogeneous differential equation with constant coefficients. Show more…
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