Question

Consider the following figure. 7.00 ? 4.00 ? 9.00 ? R (a) Find the equivalent resistance between points a and b in the figure. ($R = 16.0 \Omega$) ? (b) Calculate the current in each resistor if a potential difference of 40.0 V is applied between points a and b. $I \ (4.00 \Omega) =$ $A$ $I \ (7.00 \Omega) =$ $A$ $I \ (16.0 \Omega) =$ $A$ $I \ (9.00 \Omega) =$ $A

          Consider the following figure.
7.00 ?
4.00 ?
9.00 ?
R
(a) Find the equivalent resistance between points a and b in the figure. ($R = 16.0 \Omega$)
?
(b) Calculate the current in each resistor if a potential difference of 40.0 V is applied between points a and b.
$I \ (4.00 \Omega) =$
$A$
$I \ (7.00 \Omega) =$
$A$
$I \ (16.0 \Omega) =$
$A$
$I \ (9.00 \Omega) =$
$A

Consider the following figure.
7.00 ?
4.00 ?
9.00 ?
R
(a) Find the equivalent resistance between points a and b in the figure. (R = 16.0 Ω)
?
(b) Calculate the current in each resistor if a potential difference of 40.0 V is applied between points a and b.
I (4.00 Ω) =
A
I (7.00 Ω) =
A
I (16.0 Ω) =
A
I (9.00 Ω) =
A

Added by Vincent G.

Fundamentals of Physics

David Halliday, Robert Resnick, Jearl… 8th Edition

Chapter 28

Instant Answer

Solved by Expert Christopher Dzorkpata

Step 1

$R_{cd}$ is the parallel combination of $R$ (16.0 Ω) and 7.00 Ω. $\frac{1}{R_{cd}} = \frac{1}{16.0} + \frac{1}{7.00}$ $\frac{1}{R_{cd}} = \frac{7.00 + 16.0}{16.0 \times 7.00} = \frac{23.0}{112}$ $R_{cd} = \frac{112}{23.0} \approx 4.87 \, \Omega$ Show more…

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Consider the following figure. 7.00 Ω 4.00 Ω 9.00 Ω R (a) Find the equivalent resistance between points a and b in the figure. ($R = 16.0 \, \Omega$) (b) Calculate the current in each resistor if a potential difference of 40.0 V is applied between points a and b. $I_{(4.00 \, \Omega)} = $ $I_{(7.00 \, \Omega)} = $ $I_{(16.0 \, \Omega)} = $ $I_{(9.00 \, \Omega)} = $