Question

Consider the following frequency table representing the scores on a test. Scores on a Test Class Frequency 40–60 22 61–81 15 82–102 11 103–123 14 124–144 11 Step 1 of 5: Determine the lower class boundary for the fourth class. Step 2 of 5: Determine the upper class boundary for the third class. Step 3 of 5: Determine the class width of each class. Step 4 of 5: Choose the interval that contains the score, 104.5. Step 5 of 5: Determine the number of scores between 39.5 and 102.5.

          Consider the following frequency table representing the scores on a test.

Scores on a Test
Class
Frequency
40–60
22
61–81
15
82–102
11
103–123
14
124–144
11

Step 1 of 5: 
Determine the lower class boundary for the fourth class.

Step 2 of 5: 
Determine the upper class boundary for the third class.

Step 3 of 5: 
Determine the class width of each class.

Step 4 of 5: 
Choose the interval that contains the score, 104.5.

Step 5 of 5: 
Determine the number of scores between 39.5 and 102.5.

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Added by Raquel H.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert T. L.

02/01/2023

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Consider the following frequency table representing the scores on a test. Scores on a Test Class Frequency 40–60 22 61–81 15 82–102 11 103–123 14 124–144 11 Step 1 of 5: Determine the lower class boundary for the fourth class. Step 2 of 5: Determine the upper class boundary for the third class. Step 3 of 5: Determine the class width of each class. Step 4 of 5: Choose the interval that contains the score, 104.5. Step 5 of 5: Determine the number of scores between 39.5 and 102.5.

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Transcript

00:01 Hey there, welcome to numerade.

00:03 We are given a frequency table here, summarizing these scores on a test.

00:09 So we are given five steps here in total, and we're asked to find each one.

00:14 Let's start with step number one.

00:17 Determine the lower class boundary of the fifth class.

00:22 So what we have for the fifth class is the range from, let's see, one, two, three, four, five.

00:30 So the fifth class is our last class, 56 to 59.

00:38 So let us find our upper, or sorry, lower class boundary.

00:44 So lower class boundary would equal the 56.

00:50 So we take the previous upper class of class 4, 55, plus 56, divided by 2, giving us a class boundary here, that equals 55, plus, 5 .5.

01:08 All right, so we have 55 .5.

01:11 Let's try step number two.

01:15 We have determined the upper class boundary of the second class.

01:19 So our second class here is from 44 to 47, 44 to 47, in which we have the upper class boundary, equaling the 47 and 48.

01:42 So we take 47.

01:44 Plus 48 divided by, let's see what we get here, 2 equaling 47 .5.

01:59 All right.

02:02 And then from there, we're going to move on to step three in which we're asked to determine the class width of each class.

02:10 So for each class, they will have the same class width.

02:13 So our width here basically equals the difference between two...

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