Consider the following hypotheses: ??: ? ? 155 ??: ? < 155 The population is normally distributed. A sample produces the following observations: 135 155 141 153 133 143 Conduct the test at the 5% level of significance. (You may find it useful to reference the appropriate table: z table or t table) a. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic b. Find the $p$-value. 0.01 ? $p$-value < 0.025 $p$-value < 0.01 $p$-value ? 0.10 0.05 ? $p$-value < 0.10 0.025 ? $p$-value < 0.05 c. What is the conclusion? Do not reject $H_0$ since the $p$-value is less than the significance level. Do not reject $H_0$ since the $p$-value is greater than the significance level. Reject $H_0$ since the $p$-value is less than the significance level.
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Sample mean (x̄) = (135 + 155 + 141 + 153 + 133 + 143) / 6 = 140 Sample standard deviation (s) = √[((135-140)^2 + (155-140)^2 + (141-140)^2 + (153-140)^2 + (133-140)^2 + (143-140)^2) / 5] = √[200.67] ≈ 14.15 Show more…
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Consider the following hypotheses: Ho : 155 HA: 155 The population is normally distributed. A sample produces the following observations: 135 155 141 153 133 143 Conduct the test at the 5% level of significance: (You may find it useful to reference the appropriate table: z table or t table) a. Calculate the value of the test statistic: (Negative value should be indicated by a minus sign: Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places ) Test statistic b. Find the p-value. 0.01 < p-value < 0.025 p-value 0.01 p-value > 0.10 0.05 p-value < 0.10 0.025 p-value 0.05 What is the conclusion? Do not reject Ho since the p-value is less than the significance level: Do not reject Ho since the p-value is greater than the significance level: Reject Ho since the p-value is less than the significance level:
David N.
Consider the following hypotheses: H0: μ ≥ 160 HA: μ < 160 The population is normally distributed. A sample produces the following observations: 152 138 151 144 151 142 Conduct the test at the 1% level of significance. (You may find it useful to reference the appropriate table: z table or t table) a. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) b. Find the p-value. p-value < 0.01 p-value 0.10 0.05 p-value < 0.10 0.025 p-value < 0.05 0.01 p-value < 0.025 c. What is the conclusion? Do not reject H0 since the p-value is less than the significance level. Do not reject H0 since the p-value is greater than the significance level. Reject H0 since the p-value is less than the significance level. Reject H0 since the p-value is greater than the significance level. d. Interpret the results α = 0.01. We cannot conclude that the population mean is less than 160. We conclude that the population mean is less than 160. We cannot conclude that the population mean is greater than 160. We conclude that the population mean is greater than 160.
Madhur L.
Consider the following competing hypotheses and accompanying sample data: (You may find it useful to reference the appropriate table: z table or t table) H0: μ1 - μ2 = 6 HA: μ1 - μ2 ≠ 6 x̄1 = 59, x̄2 = 45 s1 = 23.6, s2 = 17.3 n1 = 20, n2 = 15 Assume that the populations are normally distributed with equal variances. a-1. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) Test statistic a-2. Find the p-value. p-value < 0.01 0.01 ≤ p-value < 0.02 0.02 ≤ p-value < 0.05 0.05 ≤ p-value < 0.10 p-value ≥ 0.10 b. At the 10% significance level, can you conclude that the difference between the two means differs from 6? H0. At the 10% significance level, we conclude that the difference between the means differs from 6.
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